A cable provider wants to contact customers in a particular telephone exchange to see how satisfied they are with the new digital TV service the company has provided. All numbers are in the 590 ​exchange, so there are 10 comma 000 possible numbers from 590​-0000 to 590​-9999. If they select the numbers with equal​ probability: ​a) What distribution would they use to model the​ selection? ​b) What is the probability the number selected will be an odd ​number? ​c) What is the probability the number selected will end in 999​?

Answer:a) Discrete Uniform Distributionb) 0.5c) 0.001Step-by-step explanation:a) What distribution would they use to model the selection? Since each number has equal probability of being selected, they would be using a Discrete Uniform Distribution. b) What is the probability the number selected will be an odd number? Since there are 5,000 odd numbers between 0 and 9999 P(odd)=5,000/10,000 = ½ = 0.5 c) What is the probability the number selected will end in 999? There are only 10 numbers ending in 999: 0999, 1999, 2999,...,9999 hence P(number ends in 999)=10/10,000 = 1/1,000 = 0.001