The perimeter of a rectangle is twice the sum of its length and it’s width . The perimeter is 22 meters and I it’s length is 2 meters more then twice it’s width. What’s its length?
Accepted Solution
A:
Answer:The length of this rectangle is 8m.Step-by-step explanation:The problem states that the perimeter of a rectangle is twice the sum of its length and it’s width. So[tex]P = 2*l + 2*w[/tex]The problem also states that the perimeter is 22 meters. So:[tex]P = 22[/tex][tex]2l + 2w = 22[/tex].Also, it states that I is the length and it is 2 meters more then twice it’s width. So[tex]l = 2w + 2[/tex]What’s its length?[tex]P = 22[/tex][tex]2l + 2w = 22[/tex][tex]2(2w+2) + 2w = 22[/tex][tex]4w + 4 + 2w = 22[/tex][tex]6w = 22 - 4[/tex][tex]6w = 18[/tex][tex]w = \frac{18}{6}[/tex][tex]w = 3[/tex]The width is 3m. The length is in function of the width, so:[tex]l = 2w + 2[/tex][tex]l = 2*3 + 2[/tex][tex]l = 8m[/tex]The length of this rectangle is 8m.